[Programmers][SQL] 오랜 기간 보호한 동물(1), (2) (59044번) - MySQL Solution

문제

• https://programmers.co.kr/learn/courses/30/lessons/59044
• https://programmers.co.kr/learn/courses/30/lessons/59411

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Solution - 오랜 기간 보호한 동물(1)

SELECT INS.NAME, INS.DATETIME
FROM ANIMAL_INS AS INS LEFT JOIN ANIMAL_OUTS AS OUTS ON INS.ANIMAL_ID = OUTS.ANIMAL_ID
WHERE OUTS.DATETIME IS NULL
ORDER BY INS.DATETIME
LIMIT 3

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Solution - 오랜 기간 보호한 동물(2)

SELECT OUTS.ANIMAL_ID, OUTS.NAME
FROM ANIMAL_OUTS AS OUTS, ANIMAL_INS AS INS
WHERE OUTS.ANIMAL_ID = INS.ANIMAL_ID
ORDER BY OUTS.DATETIME - INS.DATETIME
DESC
LIMIT 2